Question

33. An electric refrigerator rated 400W operates 10 hours per day. What is the cost of energy
to operate it for 30 days at 3.00 per kWh
?​

Answer 1

Answer:

Energy of one day =Power×Time=400W×8h=3.2KWh

Energy of 30 days =3.2KWh×30=96KWh

So, cost of the energy =96×3=Rs.288

Answer 2

Answer:

Explanation:

Given: (P) = 750 W

= 750

1000

kW = 75

100

(t) = 2 × 30 = 60 hours

Unit cost = ` 3

To find: Total Cost = ?

Formula: H = P × t

Solution: H = P × t