Chemistry, asked by arifhmohd, 7 months ago

33. BeCl, on hydrolysis exists as
(a) Be(OH)2
(b) [Be(OH).12-
(C) [Be(OH)4]2-
(d) None of these is correct​

Answers

Answered by swtee
4

Option B is correct answer

Answered by PhysicsForever
0

Answer:

First Be(OH)2 is formed but later a stable complex of [Be(OH)4]2- is formed so correct answer is (c)

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