33. BeCl, on hydrolysis exists as
(a) Be(OH)2
(b) [Be(OH).12-
(C) [Be(OH)4]2-
(d) None of these is correct
Answers
Answered by
4
Option B is correct answer
Answered by
0
Answer:
First Be(OH)2 is formed but later a stable complex of [Be(OH)4]2- is formed so correct answer is (c)
Similar questions