Question

33. Calculate the de-Broglie wave length of the electron in the ground state of hydrogen atom, given
that its kinetic energy is 13.6 eV. (1eV = 1.602 x 10^-19J)
(a) 3.328 x 10^-10 m
(b) 2.338 x 10^-10 m
(C) 3.328 x 10^10 m
(d) 2.338 x 10 m​

Answer 1

Answer:

(a)3.328*10^-10

Explanation:

de broglie wavelength =h/√2mKE(in joule)