Question

(33)
Factorise
25a2 + 20ab + 4b^2 - 49c2​

Answer 1

Answer:

$(5a+2b+c)(5a+2b-c)$

Step-by-step explanation:

$a^2+2ab+b^2=(a+b)^2$ --- 1

$a^2-b^2=(a+b)(a-b)$ --- 2

$25a^2+20ab+4b^2-c^2$

→ $(5a)^2+2\times 5a\times 2b+(2b)^2-c^2$

→ $(5a+2b)^2-c^2$ From 1

→ $(5a+2b+c)(5a+2b-c)$ From 2 - Irreducible Factorization

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