Question

33. Find the area of the quadrilateral ABCD whose vertices are respectively A(1, 2) , B(7, - 2) . C(12, 3) and D(7, 22) .

Answer 1

Answer:

The coordinates of A,B,C & D are A(1,1),B(7,3),C(12,2),D(7,21).

Area of quadrilateral ABCD = Area of triangle ABC + Area of triangle ACD

Area of triangle =

2

1

∣[x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)]∣

Area of triangle ABC =

2

1

∣[1(3−2)+7(2−1)+12(1−3)]∣

=

2

1

∣[1+7−24]∣

=

2

1

(16)=8 sq. units

Area of triangle ACD =

2

1

∣[1(2−21)+12(21−1)+7(1−2)]∣

=

2

1

∣[−19+240−7]∣

=

2

1

(214)=107 sq. units

Hence, area of quadrilateral ABCD = 107+8=115 sq. units

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Answer 2

Answer:

ans is 107 unt square m

Step-by-step explanation:

you can solve the question