Question

33.
Find the particular solution of the following differential equation satisfying
given condition :
(x + y + 5) dy + (3x + 3y + 1) dx = 0, y = 1 when x = 1​

Answer 1

Answer:

Step-by-step explanation:

as given , x=1=y

dx=0

(x+y+5)dy+(3x+3y+1)

x+y+5=7and 7*0=0

so, 0+3+3+1=7 answer is 7