Question

33. How much coulomb charge is present on 1g ion
of n^3
(a) 5.2x10^6 Couloumb (b) 2.894 x 10^5 Couloumb
(c) 6.6x10^6 Couloumb (d) 8.2 x 10^6Couloumb​

Answer 1

Answer:

2.89×10^5 coulomb

Explanation:

Charge on 1 mole of electrons=96500 coulomb

Charge in N^-3 means charge in 3 electrons

Charge in 1g ion means charge in 1 mole

Therefore the answer is 96500×3×1

=289500 coulomb

=2.89×10^5 coulomb

Answer 2

1. Question⇒  How much coulomb charge is present on 1g ion  of n^3?

• Your solution is right but the question you ask for might be

• for 1 g-ion. 1 g-ion = (weight in grams of sum of atomic weight of atoms making the ion.)

• Here N^3- has 14 amu so 1g-ion 14 gm.

• So here we have to find for 14g that is 1mole of nitride ion. 1 ion of nitride has =1.6 ×10^-19 × 3 C

• Therefore 6.022 × 10^23 ions has = 6.022 × 10^23 ×1.6 ×10^-19 × 3 C = 2.89 × 10^5 C.