Question

33. I started on my bicycle at 7 a.m. to reach a certain place. After going a certain distance,
my bicycle went out of order. Consequently, I rested for 35 minutes and came back to
my house walking all the way. I reached my house at 1 p.m. If my cycling speed is
10 kmph and my walking speed is 1 kmph, then on my bicycle I covered a distance
of:
(a) 4 0 1 km (6) 13 km (c) 14 km (2) 15 km
O
67
A drives during the first hour at an average snoad​

Answer 1

Answer:

In my opinion the options are wrong. It should be--

1. 4.92 km
2. 13.44 km
3. 14.375 km
4. 15.476 km

And the answer is came out approximately 5km.

so we can say option one is correct i.e 4.92 km

Answer 2

Q-A started on my bicycle at 7 a.m. to reach a certain place. After going a certain distance his bicycle went out of order. Consequently, A rested for 35 minutes and came back to his house walking all the way A reached my house at 1 p.m. If his cycling speed is 10 kmph and his walking speed is 1 kmph, then on his bicycle A covered a distance of :

(a) $4\frac{61}{66} km$

(b) $13\frac{4}{9} km$

(c) $14\frac{3}{8} km$

(d) $15\frac{10}{21} km$

A- Option(a) is the correct answer.

Given,

He started his journey at 7 a.m.

His journey was completed at 1 p.m.

Cycling speed = 10kmph

Walking speed = 1kmph

Rest time = 35 minutes

To Find,

The distance covered on the bicycle =?

Solution,

Let the time taken riding a bicycle be t

Total distance traveled on bicycle = Speed * Time = 10 * t

Total time taken in journey = 6 hours

Time taken for resting = 35 minutes = (35 / 60) hours

Total time taken = Time taken for resting, walking and riding bicycle

6 = (35/60) + Time taken for walking + t

Time taken for walking = [6 - (35/60) - t]

Time taken for walking = [(360 - 35)/60) - t]

Time taken for walking = [(325 / 60) - t] hours

Distance traveled by walking = Speed * Time = 1 *  [(325 / 60) - t]

Distance traveled by walking =  [(325 / 60) - t] km

Now, distance covered on bicycle = distance covered by walking

10t =  [(325 / 60) - t]

10t + t = 325 / 60

11t = 325 / 60

t = 325 / 660

Total distance traveled on bicycle = 10*t = 10*(325/660)

Total distance traveled on bicycle = 325 / 66

Total distance traveled on bicycle = $4\frac{61}{66}$ km

Hence, the distance covered on the bicycle is $4\frac{61}{66}$ km.