33. If the earth is one half its present distance from the sun. How many days will
be presents one year on the surface of earth will change ?
Answers
One year will contain 236 days if the distance changes.
Explanation:
Time for one revolution, T1 = 365 days
Distance from the sun, r1 = r
After the change, r2 = r / 2. T2 to be found.
We know that square of T2/ square of T1 = cube of r2 / cube of r1
Applying root on both sides, we get:
T2 / T1 = r2^(3/2) / r1^(3/2)
T2 = T1 * r2^(3/2) / r1^(3/2)
= 365 * ((r/2) / r)^(3/2)
Decrease in time of one revolution is 129 days.
So time of one revolution at the new distance = 365 - 129 = 236 days.
Answer:
129 days
Explanation:
The duration of the year can be calculated using the Kepler’s third law which can be mathematically written as;
T^2 = a^3
Here T is the orbital period in years, and a is the radius of the distance of earth to sun, stated in Astronomical Units.
When we assume that this distance is halved, that is;
A’ = a/2
T^2 = a0.5^3 = a x 0.125
Taking square root;
T’ = T x 0.35355
T ‘ = 129 days