Question

33. Number of moles of oxygen obtained by the electrolytic decomposition of 90 g of water is:
2H20 → 2H2 + O2
​

Answer 1

Answer:

Reaction taking place:

$\sf{2H_{2}O}$ → $\sf{2H_{2} + O_{2}}$

Now:

From the equation, it is clear that 36 g of water produces 32 g of oxygen on electrolysis.

So:

90 g of water will produce:

$\implies$ $\frac{32}{36} \times 90$

$\implies$ $80$ g of oxygen

That is:

$\implies$ $\frac{80}{32} = 2.5$

Therefore:

2.5 moles of oxygen are obtained by the electrolytic decomposition of 90 g of water.

Answer 2

2.5 moles of oxygen are obtained by the electrolytic decomposition of 90 g of water