Question

33. Prove that sum of any two sides of a triangie is greater than third side.
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Answer 1

Answer:

pls mark as brainliest friend

Step-by-step explanation:

Given ΔABC,

extend BA to D such that AD = AC.

Now in ΔDBC

∠ADC = ∠ACD [Angles opposite to equal sides are equal]

Hence ∠BCD > ∠ BDC

That is BD > BC [The side opposite to the larger (greater) angle is longer] Þ AB + AD > BC ∴ AB + AC > BC [Since AD = AC)

Thus sum of two sides of a triangle is always greater than third side.

Answer 2

Answer:

Its very easy

Step-by-step explanation:

sum of triangle=180

let the sides be 15+15 ,130