Question

33.
The atomic numbers of two elements are 8 and 16 respectively. Write the
electronic configuration of these two elements. Do you keep these two
elements in the same group of the modern periodic table ? Justify your
answer. Find out which of these two elements is more electronegative. Give
reason for your answer.
RF & RR(A)-306
XXX
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Answer 1

Answer:

1--. 2,6

2--. 2,8,8

Explanation:

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Answer 2

The answers to all the questions are given below:

- The electronic configuration of the elements are:

(8) = 1s2, 2s2, 2p4

(16) = 1s2, 2s2, 2p6, 3s2, 3p4

- Yes, I will keep these two  elements in the same group of the modern periodic table.

- They belong to the same group due to their same outer electronic configuration of ns2, np4.

- The element with atomic no 8 is more electronegative than the element with atomic no 16.

- The reason is that electronegativity decreases down the group.