33. The distance covered by a body in one completa
vibration is 20 cm. The amplitude of the body i
(a) 10cm (b) 5cm (c) 15cm (d) 7.5cm
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Answer:
of particle executing S.H.M v=ω
a
2
−x
2
and acceleration, a=−ω
2
x
x= displacement at any time interval
a = amplitude=3cm
ω= angular frequency, =
T
2π
T=Time period
Now, at x=2cm
v=∣a∣
⇒ω
2
×2=ω
3
2
−2
2
⇒ω=
2
5
⇒
T
2π
=
2
5
⇒T=
5
4π
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