Question

33. The equation of the line passing through the point
(-6, 10) and perpendicular to the line 7x+8y=5
is
(1) 8x - 7y + 112 = 0 (2) 8x - 7y + 124 = 0
(3) 8x - 7y + 118 = 0 (4) 8x - 7y + 132 = 0​

Answer 1

Answer:

Option 3

Step-by-step explanation:

7x + 8y =5

y = 5/8 - 7x/8

m= -7/8

Since, the lines are perpendicular.

Then, m1m2 = -1

-7/8 × m2 = -1

= m2 = 8/7

Equation of line = y - y1 / x - x1 = m

y -10 / x + 6 = 8/7

= 7y - 70 = 8x + 48

= 7y = 8x + 118

= 8x - 7y + 118 = 0