Question

33. The hypotenuse of a right angled triangle is 6 m more than twice the shortest side.
If the third side is 2 m less than the hypotenuse, find the sides of the triangle.​

Answer 1

Answer:

Let the shortest side be X

a/q

2x=6

x=6/2

x=3m

our base is 3 m

now side of triangle=

by applying Pythagoras theorem

h^2=b^2+s^2

6^2=3^2+s^2

36=9+s^2

s^2=36-9

s^2=25

s=√25

s=5m

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Answer 2

Answer:

the shortest side is 10 m and third side is 24 m and hypotenuse is 26 m

Step-by-step explanation:

let the shortest side =x

according to the question

hypotenuse = 2x+6

and third side = 2x +6 -2= 2x+4

by pythagores th

(2x +6 )^2 = (2x+4)^2 + x^2

4x^2+36+24x = 4x^2 +16 +16x +x^2

20+8x=x^2

x^2 -8x -20 =0

x^2-10x +2x-20=0

x (x-10)+2 (x-10 )=0

(x+2) (x-10 )=0

x= -2 x=10 m

2x +4 = 2×10+4 =24m

2x+6 =2×10+6 =26 m