Question

33 / u+2 + 12/v-3=123 and 12/u+2 +33/v-3=102 solve​

Answer 1

Answer:

(33/u+2) + (12/v-3) = 123

(12/u+2) + (33/v-3) = 102

let x = (1/u+2) and y = (1/v-3)

33x + 12y = 123.............(1)

12x + 33y = 102.............(2)

Multiply eqn (1) by 12 and eqn (2) by 33

396x + 144y = 1476.................(3)

396x + 1089y = 3366.............(4)

Subtract (3) and (4)

945y = 1890

y = 2

eqn (1) becomes

33x + 12(2) = 123.

33x = 123 - 24

x = 99/33

x = 3. y = 2

1/u+2 = 3. 1/v-3 = 2

1 = 3u+6. 1 = 2v-6

1-6 = 3u 1+6 = 2v

-5/3 = u 7/2 = v