Question

3300/200V, 100KVA transformer has Nz= 80
turns. The rated secondary current 12=
Amp.
A. 30.3
B. 500
C. 50
D. 30

Answer 1

Answer:

It may be 50,30.3,500 or it can be 30.Now it's up to you to decide right answer

Answer 2

Answer:

The calculated value of the rated secondary current, I₂ is $500A$.

Therefore, option b) $500A$ is correct.

Explanation:

Data given,

The voltage at the primary end, V₁ = $3300V$

The voltage at the secondary end, V₂ = $200V$

The given value of the rated power, P = $100KV-A$ = $10^{5}V-A$

The turns, $N_{Z}$ = $80turns$

The rated secondary current, I₂ =?

As we know,

• The rated power is the product of the voltage at the primary/secondary end and the current.

Therefore, we can say that:

• The given rated power ( P ) = V₂ ( given secondary end's voltage ) × I₂ ( secondary current )

P = $V_{2} \times I_{2}$

I₂ = $\frac{P}{V_{2} }$

I₂ = $\frac{10^{5} }{200}$ = $500A$

Hence, the value of the rated secondary current, I₂, measured is $500A$.