33000 Rupees is paid off in 12 installments such that each amount is 100 rupees than preceding one
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Answered by
10
we do it by arithmetic progression
sum of AP is 30000
n=12
common difference=100
we will apply formula
Sum=(n/2){2a+(n-1)d}
33000=(12/6){2a+(11×100)}
rest you can solve and find the value of a
sum of AP is 30000
n=12
common difference=100
we will apply formula
Sum=(n/2){2a+(n-1)d}
33000=(12/6){2a+(11×100)}
rest you can solve and find the value of a
Answered by
22
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