Question

34.05 mL of phosphorus vapour weighs 0.0625 g at 546 °C and 0.1 bar pressure.What is the molar mass of phosphorus?​

Answer 1

Answer:

Explanation:

we know, from gaseous equation

PV = nRT

where, P is pressure , V is volume , n is no of mole , R is universal gas constant and T is Temperature .

we know, mole = given weight/molar weight

n = m/M , put it in above equation.

PV = mRT/M

M = mRT/PV

= 0.0625 g × 0.083 L atm/K/mol × 819K/0.1 × 0.987 atm × 0.03405 L

= 1250.4 g/mol

hence, molar mass of Phosphorus = 1250.4 g/mol