34.2 g of Sucrose is dissolved in 90 g of Water. The number of oxygen atoms in the Solution are : ?
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34 2g of sucrose (C12H22O11) are dissolved in 90g of water in a glass The number of oxygen atoms in the solutions are: (a) 3 66*1026 (b)6 6*1023 (c)3 ...
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no. of Moles of Sucrose = 34.2/342 = 0.1 gm
No. of Moles of H2O = 90/18 = 5 gm
1 mole of Sucrose contains = 11×6.022×10^23 molecules of O2
0.1 mole of Sucrose contains = 11×6.022×10^22 atoms of O2
therefore, 5 mole of H2O contains = 5×6.022×10^23 atoms of O2
= 3.66 × 10^24 atoms of O2
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