Question

34+32+30+...+10
find A.P​

Answer 1

Answer:

• a=34,
• d=32−34=−2
• a
• n
• =10
• or, a+(n−1)d=10
• or, 34+(n−1)(−2)=10
• or, −2(n−1)=−24
• or, n−1=12
• ⇒n=13
• ∴S
• 13
• =
• 2
• 13
• [2(34)+12(−2)]
• =
• 2
• 13
• ×2[34−12]
• =13×22=286.
• Please make me as brainlist

Answer 2

by using the formula

a=34, d=2 i.e a2-a1 =32-34 =-2

tn=10(the last term)

tn =a+(n-1)d

10 =34+(n-1)-2

10-34=(n-1)-2

-24/-2= n-1

12=n-1

n=13