Physics, asked by parassalonia22, 1 month ago

34. A ball is thrown vertically upwards from the ground. It crosses a point at the height of 25 m twice at an interval of 4 s. The ball was thrown with the velocity of (1) 20 m/s (2) 25 m/s (4) 35 m/s (3) 30 m/s t
please tell me ​

Answers

Answered by jspsurekha
2

Answer:

3) 30 m/s

Explanation:

Distance it has fallen is s = ut+1/2at^2

= 10×2^2

=20m

Maximum height=25+20=45m

Velocity at the bottom or the initial velocity is found as,

v^2 - u^2 = 2as

Since v = 0

u^2 = 2×10×45= 900

u= ✓900

Therefore; u = 30m/s

Similar questions