34. A ball is thrown vertically upwards from the ground. It crosses a point at the height of 25 m twice at an interval of 4 s. The ball was thrown with the velocity of (1) 20 m/s (2) 25 m/s (4) 35 m/s (3) 30 m/s t
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Answer:
3) 30 m/s
Explanation:
Distance it has fallen is s = ut+1/2at^2
= 10×2^2
=20m
Maximum height=25+20=45m
Velocity at the bottom or the initial velocity is found as,
v^2 - u^2 = 2as
Since v = 0
u^2 = 2×10×45= 900
u= ✓900
Therefore; u = 30m/s
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