Question

34.
A block of mass 2 kg is hanging with two identical massless springs as shown in figure. The
acceleration of the block just at the moment, the right spring breaks is (g= 10 m/s²)
Illicle
30°
300
leille
2 kg
(A) 10 m/s2
(B) 5 m/s2
(C) 25 m/s2
(D) 4 m/s​

Answer 1

Answer:

c is the correct answer according to me

Answer 2

Answer:

Acceleration of the block is 10 m/$s^{2}$

Explanation:

Given:

A block of mass 2kg is hanging with two identical massless springs &

g=10m/$s^{2}$

To find:

The acceleration of the block

Solution:

Massless spring: A string having negligible mass compared to that of the object connected to it is called a massless string.

Here, 'g' is the gravitational force acting upon the block when it is hanging.

Since, it is given that the block is of 2kg mass and is hanging with two identical massless springs so, the formula is given by,

⇒ 2Tcos60° = 20N

⇒ T = 20N

Acceleration of the block is, a = $\frac{T}{M}$

⇒ a = $\frac{20}{2}$

⇒ a = 10

We know that the unit of acceleration is given by m/$s^{2}$

Hence, the acceleration of the 2kg block which is hanging with two identical massless springs is given by 10 m/$s^{2}$.

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