Question

34) A body is starting from rest and is subject to a uniform acceleration
of 10 m/s2 Determine
a) Velocity of the body at the end of 5s.
b) Displacement of the body in first 3s.
c) Time taken to cover a distance of 20m.
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Answer 1

Step-by-step explanation:

Initial velocity, u = 0 acceleration, a = 10ms-2 time, t = 5s, v = ? From, the Equation, v = u + at we have, v = 0 + 10 × 5 v = 50 ms-1 2. Initial velocity, u = 0 acceleration a = 10 ms-2 time, t = 36s Distance travelled, s = ? From the equation s = ut + 1/2 at2 we have = 0 + 1/2 × 10 × 9 s = 45 m 3. Initial velocity u = 0, acceleration a = 10ms-2 Displacement s = 20m velocity v = ? From the equation v2 = u2 + 2as, = 02 + 2 × 10 × 20 = 400 v = √400 = 20ms-1 4. Initial velocity u = 0 Acceleration a = 10ms-1 n = 4 sec Displacement S4 = ? From the Equation, Sn = u + a/2 (2n - 1) S4 = 0 + 10/2 (2 × 4 – 1) = 0 + 5(7) S4 = 35m.Read more on Sarthaks.com - https://www.sarthaks.com/585692/a-body-is-starting-from-rest-and-is-subjected-to-a-uniform-acceleration-of-10ms-2-determine?show=585713#a585713

Answer 2

Answer:

Here :

u=0 (initial velocity) , a=10 m/s^2

(a) Using formula v=u+at

v= 0+ 10 ×5

v= 50 m/s^2

(b) using formula s= ut +1/2 at^2

s= 0+1/2× 10×9

s= 45 m

(c) using formula s= ut +1/2 at^2

20 = 0 + 1/2×10 t^2

20 = 5 t^2

t^2 = 4

t = 2

Hope it helps you