Question

34 a cylinder of curved surface area 1152m²
is formed from a retangular métallic
Sheet. Find the dimensions of the rectangul
if its length is double of its
breadth:
ar sheet​

Answer 1

Step-by-step explanation:

Given :

Curved Surface Area (CSA) = 1250m²

According to the question,

The cylinder is formed into a rectangular metallic sheet.

Also,

given : The length of the rectangular sheet is double its breadth.

Let,

breadth be \bf{b}b m

length = \bf{2b}2b m

So,

\bf{Area\: of\: the\: rectangular\: sheet = CSA\: of \:cylinder }Areaoftherectangularsheet=CSAofcylinder

=> length × breadth = 1250

=> \bf{2b}2b ×\bf{b}b = 1250

=> \bf{2b}2b ² = 1250

=> \bf{b}b ² = \frac{1250}{2}

2

1250

=> \bf{b}b ² = 625

=> \bf{b}b = \sqrt{625}

625

=> \bf{b}b = 25

Therefore, breadth (\bf{b}b ) = 25 m,

and length = 2b = 2×25 = 50 m