Question

34. A force of 10 N acts for 20 second on a body of mass 2 kg initially at rest. Calculate the energy required

by the body and the work done by the applied force.​

Answer 1

U=0m/s

F=ma

a=F÷m

So,a=10÷1=10

S=ut+1/2 at×t

=1/2 ×10×16

=80

W=FS

10×80

=800J

Answer 2

Answer:

10000J

Explanation:

F=10

M=2

a=F/M

= 10/2

= 5m/s^2

t = 20 s

v= u+at

= 0+5X20 = 100 m/s

KE = 1/2mv^2 = 1/2 X 2 X (100)^2

= 10000 J

hope it helps you