Question

34.
A particle A of mass 10/7 kg is moving in the
positive direction of x. Its initial position is x =
O and initial velocity is 1 m/s. The Velocity at
x = 10 is :
XXX​

Answer 1

Answer:

Answer :

120

Solution :

3y=4x+10

∣∣p→∣∣=mv=10×6=60kgm/s

The ⊥ distance form origin on line

=−0'+0+10(3)2+(4)2−−−−−−−−−√=1056=2m

|L|=P×⊥dist=(60)(2)=120kg−m2/s.

Alternatively

tanθ=4/3

θ=53∘

r=52sin53∘=2m

L=rP⇒L=rmv

L=2×10×6

L=120Kg−m/s.