Question

34. An open-ended U-tube of uniform cross-sectional area
contains water (density 1.0 g/cm) standing initially 20
cm from the bottom in each arm. An immiscible liquid of
density 4.0 g/cm² is added to one arm until a layer 5 cm high
forms, as shown in the figure above. What is the rat
of the heights of the liquid in the two arms?
15 cm
(1) 3/1
$
2/1
(2) 5/2
(4) 3/2​

Answer 1

The ratio between the heights of the liquid in the two arms is 2/1.

Option (c) is correct.

Explanation

Given data:

Length "L" = 40 cm

P1 = P2

5 x 4 x g = (x) x g x 1

x = 20 cm

Now find the ratio in the heights:

h2/h1 = x + y/ 5 + y

Since

x + y + y = 40

and 2y = 20 then y = 10

Now

h2/h1  = 30 /15

h2/h1  = 2/1

Thus the ratio between the heights of the liquid in the two arms is 2/1.

Also learn about

what is ratio and proportion​ ?

https://brainly.in/question/8859892