Question

34) Construct a triangle xyz in which and xy + yz+zx=11cm.
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Answer 1

Answer:

step by construction

1). Draw a line segment AB equal to XY+YZ+ZX=11cm

2) Make angle equal to angle y=30 from point A.let the angle be angle LAB

3) Make angle equal to angle z =90 from point B. let the angle be angle MBA

4)Bisect angle LAB and angle MBA .

These Bisect at point X.

5)make a perpendicular bisector of XA.

let if interest AB at point Y .

6) make perpendicular bisector of XB.

let if interest AB at point Z.

7) join XY and XZ

therefore, ∆xyz is the required ∆