34) Construct a triangle xyz in which and xy + yz+zx=11cm.
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step by construction
1). Draw a line segment AB equal to XY+YZ+ZX=11cm
2) Make angle equal to angle y=30 from point A.let the angle be angle LAB
3) Make angle equal to angle z =90 from point B. let the angle be angle MBA
4)Bisect angle LAB and angle MBA .
These Bisect at point X.
5)make a perpendicular bisector of XA.
let if interest AB at point Y .
6) make perpendicular bisector of XB.
let if interest AB at point Z.
7) join XY and XZ
therefore, ∆xyz is the required ∆
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