Question

34. Find the value of a and b in 5+2√3÷7+4√3=a+b√3​

Answer 1

Answer:

a==11,b= -6

Step-by-step explanation:

i can't explain this

Answer 2

$\mathfrak{\huge{Answer:-}}</p><p> \\ \bold{\frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } = a + b \sqrt{3} } \\ \frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } \times \frac{7 - 4 \sqrt{3} }{7 - 4 \sqrt{3} } = a + b \sqrt{3} \\ \frac{(5 + 2 \sqrt{3})(7 - 4 \sqrt{3})}{(7 + 4 \sqrt{3})(7 - 4 \sqrt{3})}= a + b \sqrt{3} \\ \frac{5(7 - 4 \sqrt{3}) + 2 \sqrt{3}(7 - 4 \sqrt{3})}{ {(7)}^{2} - {(4 \sqrt{3})}^{2}} = a + b \sqrt{3} \\ \frac{35 - 20 \sqrt{3} + 14 \sqrt{3} - 24 }{49 - 48}= a + b \sqrt{3} \\ \frac{11 - 6 \sqrt{3} }{1} = a + b \sqrt{3} \\ 11 - 6 \sqrt{3} = a + b \sqrt{3} \\\boxed{\boxed{\large{\bold{a = 11, \: b = ( - 6)}}}}$