Physics, asked by kik85609, 5 months ago

34. Force between two identical charges placed at a distance of r in vacuum is F. Now a slab of dielectric constant is inserted between these two charges. If the Thickness of the slab is r/2, then the force between the charges ​

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Answered by nidhi213688
0

Answer:

good night..... ghost dreams...

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Answered by aishanibanerjee2704
7

Answer:

given, force between particles placed at a distance of r in vaccum is F. hence, force between the charges will become 4F/9. Hope it helps. Please follow me

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