Question

34. In the given figure ABCD is parallelogram and DE is perpendicular to AB. and BE = 16 cm.
Find area of the shaded region.
34 cm
10 cm
E 16 cm​

Answer 1

Step-by-step explanation:

AREA OF PARALLELOGRAM = b*h

34*10 = 340 cm^2

AE= 18

AREA OF THE TRIANGLE = 1/2 *b*h

1/2* 10 * 18= 90 cm^2

Area of shaded region = 340 - 90

= 250 cm^2

Answer 2

Answer:

The Area of the shaded region=250cm²

Step-by-step explanation:

• A parallelogram is a 2-dimensional figure whose opposite sides are equal and parallel.
• The area of Parallelogram is given by  

        $A=l\times h$

• The area of a triangle is given by

       $A=0.5bh$

Step 1 of 1:

• Length of Parallelogram=34 cm
• Height of Parallelogram=10 cm
• The area of Parallelogram is given by

        $A=l\times h$

        $A=10\times34\\A=340 cm^2$

• Length of the line AE=AB-EB

                                      AE=34-16

                                      AE=18 cm

• The area of the triangle is given by

        $A=0.5bh$

       $A=0.5\times18\times10\\A=90 cm^2$

• Area of the shaded region=340-90=250cm²