Question

34 litre cylinder contains 212 gram of O2 at 27 degree Celsius what mass of O2 must be released to reduce the pressure 2.463 ATM
1: 103 gram
2: 109.8 gram 3: 100 gram
4: 32 gram

Answer 1

Answer:

156.74gram

Explanation:

p= 1.24 bar

v= 34 dm2

T = (21+273) =294 k

R = 0.083dm2 bar k^-1 mol^-1

PV = nRT

n = PV /RT

= 1.24×34/ 0.083×294

= 1.727 moles

left in the cylinder = n × M

= 1.727 ×32 gmol

= 55.26 g

moles of initially = 212g

released = (212- 55.26) = 156.74 g

Hope this helps you......