Question

34. Now the sum of the ages of Shibu and Haru is 50 years. 10 years ago Haru was 5 times the age of Shiva. How old is everyone now?​

Answer 1

Answer:

Let the age of Shiva be "S" and Haru be "H".

Given:

Sum of ages of Shiva and Haru = 50 years.

S + H = 50 years -- equation (1)

10 years ago Haru was 5 times the age of Shiva.

(H - 10) = 5(S - 10)

H = 5S - 50 + 10

H = 5S - 40

Substitute H value in equation (1)

5S - 40 + S = 50

6S - 40 = 50

6S = 50 + 40

6S = 90

S = 90/6

S = 15

Substitute S value in equation (1)

H + S = 50

H + 15 = 50

H = 50 - 15

H = 35

Hence, the present ages of Shiva and Haru are 15 and 35 years.

Answer 2

Given:

➺ Sum of the ages of Shibu and Haru is 50 years

➺ 10 years ago Haru was 5 times the age of Shibu

To Find:

☛ Age of Haru and Shibu

Solution:

Let the age of Haru be x. Then,

According to the question,

x+Age of Shibu= 50

Age of Shibu= 50-x

• 10 Years Ago

➳Age of Haru= x-10

➳Age of Shibu= 50-x-10

                         = 40-x

Now,

According to the question,

x-10= 5(40-x)

⇒x-10= 200-5x

⇒x+5x= 200+10

⇒6x= 210

⇒x= 35

So,

Present age of Haru= x= 35 years

Present age of Shibu= 50-x= 50-35= 15 years

Hence, age of Haru is 35 years and age of Shibu is 15 years.