Question

34)
Prove that sine-cos8+1 = - 1
sino +cose-1 seco-tano
or
ALALA​

Answer 1

To Prove

→ (tan∅ + sec∅ - 1)/(tan∅ - sec∅ + 1) = (1 + sin∅)/cos∅

Proof

(Given in the attachment)

Procedure

Identities used in solution

tan∅ = sin∅/cos∅

sec∅ = 1/cos∅

(sin∅ + 1)² = sin²∅ + 1 + 2sin∅

(sin∅ + cos∅) = sin²∅ + cos²∅ + 2sin∅cos∅

sin²∅ + cos²∅ = 1

cos²∅ = (1 - sin²∅)

Since we got L.H.S = R.H.S

Hence Proved