Question

34)
$2 {x}^{2} - 3 {x}^{2} + 7x + 5 \\ p( - 2) =$
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Answer 1

$2 {x}^{2} - 3 {x}^{2} + 7x + 5 \\ \\ p( - 2) = 2 { (- 2)}^{2} - 3 {( - 2)}^{2} + 7 ( - 2) + 5 \\ = 2 \times 4 - 3 \times 4 -14 + 5 \\ = \: \: 8 - 12 - 14 +5 \\ = 13 - 26 = 13$

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