Question

34. The value of lamda of Al3+ is x and Cl
is y then, the value of lamdaof AlCl3,
will be 1)x/3+y 2)3x+3y 3)x/3+y/3 4)3x+y/3​

Answer 1

Answer:

1)x/3+y

Explanation:

by using kohlroch law

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Answer 2

The value of limiting molar conductivity of $AlCl_3$ is $\frac{x}{3}+y$

Explanation:

Kohlrausch law of limiting molar conductivity is defined as the sum of the limiting ionic conductivities of the cation and the anion each divided by the charge of the ion that is present in one formula unit of the electrolyte.

Mathematically,

$\Lambda^o_m\text{ for }A_xB_y=\frac{1}{y}\lambda^o_++\frac{1}{x}\lambda^o_-$

We are given a chemical formula of $AlCl_3$

The value of limiting molar conductivity for above compound follows:

$\Lambda^o_{AlCl_3}=\frac{1}{3}\Lambda^o_{Al^{3+}}+\frac{1}{1}\Lambda^o_{Cl^-}$

We are given:

$\Lambda^o_{Al^{3+}}=x\\\Lambda^o_{Cl^-}=y$

Putting values in above equation, we get:

$\Lambda^o_{AlCl_3}=\frac{x}{3}+y$

Learn more about Kohlrausch law:

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