Question

34. To a fraction, if 3 added to numerator, 4 is subtracted from denominator, the fraction becomes 2.if 2 is subtracted to from the denominator, the fraction becomes 5 by 6.find the fraction​

Answer 1

Answer:

Step-by-step explanation:

Let numerator = x ,

Denominator = y,

according to the problem given,

i) when 3 is added to the denominator and 2 is subtracted from the numerator a fraction becomes 1/4

ii)when 6 is added to numerator and denominator is multiplied by 3 it

Answer 2

$\sf \bold {Given\::}$

$\bullet$ Numerator = n

$\bullet$ Denominator = d

$\sf \bold {Given\::}$

$\bullet \sf \:\: \dfrac{n+3}{d-4} = 2\\\\\bullet \sf \:\: \dfrac{n}{d-2}\: =\: \dfrac{5}{6}$

$\sf \bold {To\find\::}$

$\bullet \sf \:\:\:\dfrac{n}{d}$

$\sf \bold {Solution\::}$

$\implies \sf \dfrac{n+3}{d-4} = 2\\\\\implies \sf n+3 = 2(d-4)\\\\\implies \sf n + 3 = 2d - 8\\\\\implies \sf n = 2d - 8 -3 \\\\\implies \sf n = 2d - 11 \:\:...... equation 1\\\\\\\implies \sf \dfrac{n}{d-2} = \dfrac{5}{6} \\\\\implies \sf n \times 6 = 5(d-2)\\\\\implies \sf 6n = 5d - 10\\\\\sf putting\: value\: of \: n \:from\: equation\:1\:in\: equation\:2\\\\\implies \sf 6(2d-11) = 5d - 10\\\\\implies \sf 12d - 66 = 5d - 10\\\\\implies \sf 12d-5d = 66-10\\\\\implies \sf 7d = 56$

$\implies \sf d = 56/7\\\\\implies \sf d = 8$

Putting value of d in equation 1

n = 2d-11

n = 2(8)-11

n = 16-11

n = 5

$\sf \bold {ANSWER\::}$$\sf \dfrac{n}{d} = \bold{\dfrac{5}{8} }$