342:20::266:?::399:23
Answers
Answered by
5
Step-by-step explanation:
Given expression is valid when x>−1, x<1, x
2
<1
Therefore, x∈(−1,1)
But for x=0, L.H.S
=R.H.S
Thus x∈(−1,1)−{0}⇒(1)
log
10
1+x
+log
10
(
1−x
)+2log
10
(
1−x
)=log
10
1−x
2
+2
Answered by
17
Step-by-step explanation:
it is very simple
first tried
it's Isha
drop some thx
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