Question

342gm of sugar was dissolved in water to produce 214.2g of sugar syrup .calculate molality and mole fraction of sugar in syrup​

Answer 1

Answer:

Molar mass of sugar(C6H12O6) = 180 gm/mole

Molar mass of water = 18 gm/mole

No. of moles of sugar = given mass/ molar mass

= 342/180 mole

= 1.9 mole

No. of moles of water = 214.2/18 mole

= 11.9 mole

Molality(m) = no. of moles of solute/ mass of solvent(kg)

m = 1.9/0.2142 molal

= 8.87 molal

mole fraction of sugar = 1.9/(1.9+11.9)

= 1.9/13.8

= 0.14

mole fraction of water = 11.9/13.8

= 0.86

Hope it will help you