343a2+512b3 factorisation
Anonymous:
i think it will be 343a³+512b³ not what u gave
yes
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343a³+512b³
(7a)³+(6b)³
using a³+b³ = (a+b)(a²+b²-ab)
(7a+6b)[(7a)²+(6b)²-7a×6b]
(7a+6b)(49a²+36b²-42ab)
Hope this helps
(7a)³+(6b)³
using a³+b³ = (a+b)(a²+b²-ab)
(7a+6b)[(7a)²+(6b)²-7a×6b]
(7a+6b)(49a²+36b²-42ab)
Hope this helps
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