Math, asked by sandhyanarvekar84, 3 days ago

35×23
what is the number Representing the error in the above example ?​

Answers

Answered by world0of0study
2

Answer:

Examples:

When your instrument measures in "1"s

then any value between 6½ and 7½ is measured as "7" accuracy 1: 6.5 to 7.5

When your instrument measures in "2"s

then any value between 7 and 9 is measured as "8" accuracy 2: 7 to 8

Error?

No ... you didn't measure it wrong ... this is about accuracy

Answered by Sreejanandakumarsl
0

Answer:

200 and 60 are the errors in the number representing in the question.

Step-by-step explanation:

Lets see an example of 35 x 23 according to the question by using lattice method is :

\left[\begin{array}{ccc}x&30&5\\200&60&100\\3&90&15\end{array}\right]

We are supposed to find the number that is indicating an error in the above lattice method.

  • The lattice method can be used to multiply integers instead of using lengthy multiplication.
  • In this method, a lattice that is sized to fit the integers being multiplied is first built.
  • The size of the lattice is mn if we are multiplying an m-digit number by an n-digit number.
  • Each digit of the multiplicand serves as the header for one column of cells by being positioned along the top of the lattice (the most significant digit is put at the left).
  • Each digit of the multiplier serves as a (trailing) header for one row of cells by being positioned along the right side of the lattice (the most significant digit is put at the top)

Solution :

By using 35 x 23

We get : 35 = 30+5 and 23 = 20+3

\left[\begin{array}{ccc}x&30&5\\20&600&100\\3&90&15\end{array}\right]

The sum of the above lattice is = 600 + 100 + 90 + 15 = 805

Hence we can say that by our above calculation 35 x 23 = 805

\left[\begin{array}{ccc}x&30&5\\20&600&100\\3&90&15\end{array}\right]

Therefore we can say that the correct lattice is :

\left[\begin{array}{ccc}x&2\30&5\\20&600&100\\3&90&15\end{array}\right] and the lattice that is given to us is not accurate

Hence 200 in the lattice should be 20 and instead of 600 it should be 60.

Therefore we can say that 200 and 60 are the errors in the given question.

#SPJ3

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