Question

35.5 g of chlorine occupies 11,200 cm³ at S.T.P. 35.5 g of chlorine occupies 11,200 cm³ at S.T.P. We have to calculate the atomicity of chlorine. 35.5 g of chlorine occupies 11,200 cm³ at S.T.P. We have to calculate the atomicity of chlorine. As we know 1 mole of any particular substance is equal to 1 g molecular mass of it. i.e., 1 mole of substance = 1 g molecular mass of it 1 gram of chlorine occupies how much ? 1 gram of chlorine occupies how much ? ==> 11200cm³ 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P. 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P.==> 22400 × 35.5 / 11200 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P.==> 22400 × 35.5 / 11200 ==> 22400 × 355 / 11200 × 10 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P.==> 22400 × 35.5 / 11200 ==> 22400 × 355 / 11200 × 10 ==> 224 × 355 / 112 × 10 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P.==> 22400 × 35.5 / 11200 ==> 22400 × 355 / 11200 × 10 ==> 224 × 355 / 112 × 10 ==> 224 × 71 / 112 × 2 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P.==> 22400 × 35.5 / 11200 ==> 22400 × 355 / 11200 × 10 ==> 224 × 355 / 112 × 10 ==> 224 × 71 / 112 × 2 ==> 112 × 71 / 112 1 gram of chlorine occupies how much ? ==> 11200cm³ Calculating grams of chlorine that will occupy 22,400 cm³ at S.T.P.==> 22400 × 35.5 / 11200 ==> 22400 × 355 / 11200 × 10 ==> 224 × 355 / 112 × 10 ==> 224 × 71 / 112 × 2 ==> 112 × 71 / 112 ==> 71 ------------------------------------------------- Thus, gram molecular mass would be 71g . Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic mass Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given, Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Solving now, Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Solving now,==> 71 × 10 / 355 Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Solving now,==> 71 × 10 / 355==> 71 × 2 / 71 Thus, gram molecular mass would be 71g .Now at last we would calculating the atomicity by using this formula: ==> Atomicity = Molecular mass / Atomic massAgain given,• Molecular mass = 71g • Atomic mass = 35.5 g Applying the required values: ==> 71 / 35.5 Solving now,==> 71 × 10 / 355==> 71 × 2 / 71 ==> 2 => atomicity of chlorine is ​

Answer 1

Answer:

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Step-by-step explanation:

Carbon dioxide is an acidic colorless gas with a density about 53% higher than that of dry air. Carbon dioxide molecules consist of a carbon atom covalently double bonded to two oxygen atoms. It occurs naturally in Earth's atmosphere as a trace gas.