Question

35.51 g of sample of oleum containing 20% free SO3 was neutralised using N/10 NaOH solution, Volume of NaOH solution in Litres required is y, then y/8 value is

Answer 1

Answer:

118% oleum means...100gm sample and 18gm is the water ... of H20=18gm... 1mol of H20 combines 1mol of so3...then 18gm of water ..

Answer 2

Explanation:

35.51 g of sample of oleum containing 20% free SO3 was neutralised using N/10 NaOH solution, Volume of NaOH solution in Litres required is y, then y/8 value is