Question

35,
5g of ethane are confined in a bulb of 1 lit. capacity.
The bulb is so weak that it will burst if the pressure
exceeds 10 atm. At what temperature will be the
pressure of gas reach the bursting value.
(1) 157.81 °C
(2) 257.81 °C
(3) 457.81°C
(4) 357.81°C​

Answer 1

Answer:  $457.81^0C$

Explanation:

To calculate the temperature of gas, we use the equation given by ideal gas equation:

$PV=nRT$

Number of moles (n) can be written as: $n=\frac{m}{M}$

where, m = given mass

M = molar mass

$PV=\frac{m}{M}RT$

where,

m = given mass = 5 g

M = molar mass of ethane = 30 g/mol

R = Gas constant = $0.08206\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the gas = ?

P = pressure of the gas = 10.0 atm

V = volume of the gas = 1 L

Putting values in equation 1, we get:

$10.0atm\times 1L=\farc{5}{30}0.08206 \times T$

$T=730.8K=(730.8-273)^0C=457.8^0C$

Thus the temperature at which the  pressure of gas reach the bursting value is $457.81^0C$

Answer 2

Explanation:

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