Question

35. A box of mass m= 6 kg slides with speed v=4m/s across a frictionless floor. It
suddenly explodes into two pieces. One piece, with mass m, = 2kg moves in the same
direction with speed.
Vi=8m/s. Find the velocity of the second piece.
A. 2 m/s
D. 9 m/s
B. 4 m /s
E. 11 m/s
C. 8 m /s​

Answer 1

Answer:A 2m/s

Explanation:

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Answer 2

Answer:

A)2 m/s

Explanation:

Mass of box, M=6kg

Speed,V=4 m/s

Momentum of box=M×V=6×4=24

a/q,

Box explodes into two pieces;

Mass of 1st piece, m1= 2kg

Mass of 2nd piece, m2= M-m1=6-2=4kg

speed of 1st piece, v1=8m/s

let the speed of 2nd piece be v2.

Now, by law of conservation of momentum:

MV= m1v1+m2v2

24= 2×8+4×v2

4×v2= 24-16= 8

v2= 8/4= 2m/s

The speed of the 2nd piece, v2= 2m/s.

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