Question

35) A disc is in the condition of pure rolling on the horizontal surface . the velocity of the centre of mass is v.if the radius of disc is R .then the speed of point P is

Answer 1

Answer:?????

Explanation:

Answer 2

Answer:

(3) $\sqrt{7}$v₀/3

Explanation:

angular velocity of the disc ω=v₀/R

as given OP=R/3 ⇒ω=v₀/R · R/3 = v₀/3. this is the velocity of point P in direction perpendicular to OP  =V t

velocity of the point p in the horizontal direction  is already mentioned in the question = V h =v₀

Resultant velocity at point P is given by V =$\sqrt{(Vh)^{2} +(V t)^{2} +2(Vh).(V t).cos 120$

[cos 120 as the angle between V h and V t is found to be 120°]

{angle between V₀ P & OP =30°. V t is perpendicular to OP.}

⇒V = $\sqrt{7}$ v₀/3.

note: v₀ replaved by v