Question

35. A motor of power 1 kilowatt lifts water 10 m high. Find (i) work done by the motor in 1 hour, (ii) total
mass of the water lifted by the motor during 1 hour. (g=10 N/kg) ​

Answer 1

Answer:

work done =power x time

so w=1000*3600[ time is 1 hr given].........(I)

w is also mgh

so mgh=1000*3600. using equation 1

m=1000*3600/100.

we get m=36000kg

note w is work done

Answer 2

Answer:

workdone=potential enrgy X time

m X g X h =p X t

m X 10 X 10 =3.6 X 10³+³

m=3.6 X 10³+³

10²

=3.6 X 10²+² kg

Step-by-step explanation:

workdone=potential enrgy X time

m X g X h =p X t

m X 10 X 10 =3.6 X 10³+³

m=3.6 X 10³+³

10²

=3.6 X 10²+² kg