Question

35. A race track is in the form of a ring whose inner circumference is 440m and
the outer circumference is 616m. Find the width of the track.​

Answer 1

Answer:

7 m

Step-by-step explanation:

let the radius of inner track = r

2 pie r = 352

r = 56

let the radius of outer track = R

2 pie R = 396

R = 63

width of track = radius of outer track - radius of inner track

=63 - 56

= 7 m

Brainliest please

Answer 2

Answer:

Let the radius of the outer circle be R, inner circle be r

Outer circumference =506m

=>2×

7

22

×R=506m

=>R=80.5m

Inner circumference =440m

=>2×

7

22

×r=440m

=>r=70m

Hence, width of the track =80.5−70=10.5m

solution