Question

35.
A vertical tower PQ subtends equal angle of 30° at each of the two places A and B, 60 meter
apart on the ground. If AB subtends an angle of 60° at P(the foot of the tower) then the height of
the tower is
(A) 203 meter
(B) 20 meter
(C) 60 V3 meter
(D) 60 meter​

Answer 1

Answer:

Step-by-step explanation:

the triangle ABP s isosceles wid centrl angle=120...AB=60..AP=BP=60/rt 3=20 rt 3...

height f tower=20 rt3/rt 3=20..!!!

Answer 2

the triangle ABP s isosceles with centrl angle=120

AB=60

AP=BP=60/rt

3=20 root3

height of tower=

20 rt3/rt 3=20..!!!

(A) 203 meter

(B) 20 meter✔️✔️

(C) 60 V3 meter

(D) 60 meter