35.
A vertical tower PQ subtends equal angle of 30° at each of the two places A and B, 60 meter
apart on the ground. If AB subtends an angle of 60° at P(the foot of the tower) then the height of
the tower is
(A) 203 meter
(B) 20 meter
(C) 60 V3 meter
(D) 60 meter
Answers
Answered by
1
Answer:
Step-by-step explanation:
the triangle ABP s isosceles wid centrl angle=120...AB=60..AP=BP=60/rt 3=20 rt 3...
height f tower=20 rt3/rt 3=20..!!!
Answered by
2
the triangle ABP s isosceles with centrl angle=120
AB=60
AP=BP=60/rt
3=20 root3
height of tower=
20 rt3/rt 3=20..!!!
(A) 203 meter
(B) 20 meter✔️✔️
(C) 60 V3 meter
(D) 60 meter
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